Namespaces
Variants
Actions

std::proj(std::complex)

From cppreference.com
< cpp‎ | numeric‎ | complex
 
C++
 
Numerics library
 
std::complex
 
Defined in header <complex>
template< class T >
std::complex<T> proj( const std::complex<T>& z );
 (1) (since C++11)
Additional overloads (since C++11)
Defined in header <complex>
(A)
std::complex<float>       proj( float f );

std::complex<double>      proj( double f );

std::complex<long double> proj( long double f );
 (until C++23)
template< class FloatingPoint >
std::complex<FloatingPoint> proj( FloatingPoint f );
 (since C++23)
template< class Integer >
std::complex<double> proj( Integer i );
 (B)
1) Returns the projection of the complex number z onto the Riemann sphere.
For most z, std::proj(z) == z, but all complex infinities, even the numbers where one component is infinite and the other is NaN, become positive real infinity, (INFINITY, 0.0) or (INFINITY, -0.0). The sign of the imaginary (zero) component is the sign of std::imag(z).
A,B) Additional overloads are provided for all integer and floating-point types, which are treated as complex numbers with positive zero imaginary component.

Contents

[edit] Parameters

z - complex value
f - floating-point value
i - integer value

[edit] Return value

1) The projection of z onto the Riemann sphere.
A) The projection of std::complex(f) onto the Riemann sphere.
B) The projection of std::complex<double>(i) onto the Riemann sphere.

[edit] Notes

The proj function helps model the Riemann sphere by mapping all infinities to one (give or take the sign of the imaginary zero), and should be used just before any operation, especially comparisons, that might give spurious results for any of the other infinities.

The additional overloads are not required to be provided exactly as (A,B). They only need to be sufficient to ensure that for their argument num:

  • If num has a standard(until C++23) floating-point type T, then std::proj(num) has the same effect as std::proj(std::complex<T>(num)).
  • Otherwise, if num has an integer type, then std::proj(num) has the same effect as std::proj(std::complex<double>(num)).

[edit] Example

Run this code
#include <complex>
#include <iostream>
 
int main()
{
    std::complex<double> c1(1, 2);
    std::cout << "proj" << c1 << " = " << std::proj(c1) << '\n';
 
    std::complex<double> c2(INFINITY, -1);
    std::cout << "proj" << c2 << " = " << std::proj(c2) << '\n';
 
    std::complex<double> c3(0, -INFINITY);
    std::cout << "proj" << c3 << " = " << std::proj(c3) << '\n';
}

Output: 

proj(1,2) = (1,2)
proj(inf,-1) = (inf,-0)
proj(0,-inf) = (inf,-0)

[edit] See also

 returns the magnitude of a complex number
(function template) [edit]
returns the squared magnitude
(function template) [edit]
constructs a complex number from magnitude and phase angle
(function template) [edit]
C documentation for cproj
Retrieved from "https://en.cppreference.com/mwiki/index.php?title=cpp/numeric/complex/proj&oldid=150886"