ispunct
From cppreference.com
Defined in header <ctype.h>
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int ispunct( int ch ); |
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Checks if the given character is a punctuation character in the current C locale. The default C locale classifies the characters !"#$%&'()*+,-./:;<=>?@[\]^_`{|}~
as punctuation.
The behavior is undefined if the value of ch is not representable as unsigned char and is not equal to EOF.
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[edit] Parameters
ch | - | character to classify |
[edit] Return value
Non-zero value if the character is a punctuation character, zero otherwise.
[edit] Example
Run this code
#include <ctype.h> #include <locale.h> #include <stdio.h> int main(void) { unsigned char c = '\xd7'; // the character × (multiplication sign) in ISO-8859-1 printf("In the default C locale, \\xd7 is %spunctuation\n", ispunct(c) ? "" : "not " ); setlocale(LC_ALL, "en_GB.iso88591"); printf("In ISO-8859-1 locale, \\xd7 is %spunctuation\n", ispunct(c) ? "" : "not " ); }
Possible output:
In the default C locale, \xd7 is not punctuation In ISO-8859-1 locale, \xd7 is punctuation
[edit] References
- C23 standard (ISO/IEC 9899:2024):
- 7.4.1.9 The ispunct function (p: TBD)
- C17 standard (ISO/IEC 9899:2018):
- 7.4.1.9 The ispunct function (p: 146)
- C11 standard (ISO/IEC 9899:2011):
- 7.4.1.9 The ispunct function (p: 202)
- C99 standard (ISO/IEC 9899:1999):
- 7.4.1.9 The ispunct function (p: 183)
- C89/C90 standard (ISO/IEC 9899:1990):
- 4.3.1.8 The ispunct function
[edit] See also
(C95) |
checks if a wide character is a punctuation character (function) |
C++ documentation for ispunct
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ASCII values | characters |
ispunct |
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