std::chrono::operator==,<=>(std::chrono::year_month_day)
From cppreference.com
| Defined in header <chrono>
|
||
constexpr bool operator==( const std::chrono::year_month_day& x,
const std::chrono::year_month_day& y ) noexcept;
|
(1) | (since C++20) |
constexpr std::strong_ordering
operator<=>( const std::chrono::year_month_day& x,
const std::chrono::year_month_day& y ) noexcept;
|
(2) | (since C++20) |
Compares the two year_month_day values x and y. This is a lexicographical comparison: the year() is compared first, then month(), then day().
The <, <=, >, >=, and != operators are synthesized from operator<=> and operator== respectively.
Return value
1)
x.year() == y.year() && x.month() == y.month() && x.day() == y.day()2) If
x.year() <=> y.year != 0, x.year() <=> y.year; otherwise if x.month() <=> y.month() != 0, x.month() <=> y.month(); otherwise x.day() <=> y.day().Notes
If both x and y represent valid dates (x.ok() && y.ok() == true), the result of the lexicographical comparison is consistent with the calendar order.
Example
Run this code
#include <chrono>
int main()
{
constexpr auto ymd1{std::chrono::day(13)/7/1337};
constexpr auto ymd2{std::chrono::year(1337)/7/13};
static_assert(ymd1 == ymd2);
static_assert(ymd1 <= ymd2);
static_assert(ymd1 >= ymd2);
static_assert(ymd1 <=> ymd2 == 0);
}