std::vector::erase
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| iterator erase( iterator pos ); iterator erase( const_iterator pos ); |
(1) | (até C++11) (desde C++11) |
| iterator erase( iterator first, iterator last ); iterator erase( const_iterator first, const_iterator last ); |
(2) | (até C++11) (desde C++11) |
Remove elementos especificados do recipiente.
1) Original:
Removes specified elements from the container.
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Remove o elemento no
2) pos.Original:
Removes the element at
pos.The text has been machine-translated via Google Translate.
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Remove os elementos da gama
[first; last).Original:
Removes the elements in the range
[first; last).The text has been machine-translated via Google Translate.
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Iterators and references to the erased elements and to the elements between them and the end of the container are invalidated.
Índice |
[editar] Parâmetros
| pos | - | iterador para o elemento a ser removido
Original: iterator to the element to remove The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
| first, last | - | intervalo de elementos para remover
Original: range of elements to remove The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. |
[editar] Valor de retorno
iterator após o último elemento removido.
Original:
iterator following the last removed element.
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[editar] Exemplo
#include <vector> #include <iostream> int main( ) { std::vector<int> c{0, 1, 2, 3, 4, 5, 6, 7, 8, 9}; for (auto &i : c) { std::cout << i << " "; } std::cout << '\n'; c.erase(c.begin()); for (auto &i : c) { std::cout << i << " "; } std::cout << '\n'; c.erase(c.begin()+2, c.begin()+5); for (auto &i : c) { std::cout << i << " "; } std::cout << '\n'; }
Saída:
0 1 2 3 4 5 6 7 8 9 1 2 3 4 5 6 7 8 9 1 2 6 7 8 9
[editar] Complexidade
1) linear in the distance between position and last.
2) linear in distance between position and the end of the container.
[editar] Veja também
| apaga o conteúdo Original: clears the contents The text has been machine-translated via Google Translate. You can help to correct and verify the translation. Click here for instructions. (função pública membro) | |
