std::inplace_vector<T,N>::pop_back
From cppreference.com
constexpr void pop_back();
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Removes the last element of the container.
If empty() is true:
- If the implementation is hardened, a contract violation occurs.
- If the implementation is not hardened, the behavior is undefined.
Iterators and references to the last element are invalidated. The end() iterator is also invalidated.
Complexity
Constant.
Example
Run this code
#include <inplace_vector>
#include <print>
int main()
{
std::inplace_vector<int, 4> numbers{1, 2, 3};
for (; not numbers.empty(); numbers.pop_back())
std::println("{}", numbers);
}
Output:
[1, 2, 3]
[1, 2]
[1]
See also
| adds an element to the end (public member function of std::inplace_vector<T,N>)
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