round(numpy.float64(0.0)) is a numpy.float64
March 22, 2018
7:05 p.m.
Hello, Is it normal, expected and desired that : round(numpy.float64(0.0)) is a numpy.float64 while round(numpy.float(0.0)) is an integer? I find it disturbing and misleading. What do you think? Has it already been discussed somewhere else? Best regards, Olivier
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josef.pktd＠gmail.com -
Nathan Goldbaum -
Nathaniel Smith -
Olivier -
Robert Kern