std::ranges::borrowed_iterator_t, std::ranges::borrowed_subrange_t

出自cppreference.com
 
 
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在標頭 <ranges> 定義
template< ranges::range R >
using borrowed_iterator_t = /* 见下文 */;
(1) (C++20 起)
template< ranges::range R >
using borrowed_subrange_t = /* 见下文 */;
(2) (C++20 起)
1)R 實現 borrowed_range 則為 std::ranges::iterator_t<R>,否則為 std::ranges::dangling
2)R 實現 borrowed_range 則為 std::ranges::subrange<std::ranges::iterator_t<R>>,否則為 std::ranges::dangling

某些受約束算法使用這兩個模板別名以避免返回潛在懸垂的迭代器或視圖。

可能的實現

borrowed_iterator_t
template< std::ranges::range R >
using borrowed_iterator_t = std::conditional_t<std::ranges::borrowed_range<R>,
    std::ranges::iterator_t<R>, std::ranges::dangling>;
borrowed_subrange_t
template< std::ranges::range R >
using borrowed_subrange_t = std::conditional_t<std::ranges::borrowed_range<R>,
    std::ranges::subrange<std::ranges::iterator_t<R>>, std::ranges::dangling>;

參閱

佔位類型,指示不應返回迭代器或子範圍,因為它可能懸垂
(類) [編輯]