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Why does basic_string::assign not have a r-value overload?
Something like assign(std::basic_string &&param);

[[Special:Contributions/167.220.236.1|167.220.236.1]] 21:49, 11 October 2015 (PDT)saurabh8c@gmail.com
:it does, it's the overload {{v|4}} on this page. --[[User:Cubbi|Cubbi]] ([[User talk:Cubbi|talk]]) 21:59, 11 October 2015 (PDT)

Why does this page say that assign(const basic_string& str) is equivalent to operator= (const basic_string& str) and may propagate allocators? The C++14/17 drafts from http://www.open-std.org appear to say that it is equivalent to assign(str, 0, npos), which in turn calls assign(str.data(), str.size()) which does not even have access to the allocator. I can see that most implementations implement assign(const basic_string&) in terms of operator= (libc++ even has tests for that) but I do not understand why.
[[Special:Contributions/80.150.243.190|80.150.243.190]] 01:27, 20 August 2019 (PDT)
: this comes from http://wg21.link/p1148 --[[User:Cubbi|Cubbi]] ([[User talk:Cubbi|talk]]) 05:35, 20 August 2019 (PDT)
:: It's actually {{lwg|2579}}; I just applied it as a drive-by when applying P1148. [[User:T. Canens|T. Canens]] ([[User talk:T. Canens|talk]]) 08:32, 20 August 2019 (PDT)

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